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Mini Long Range Distance Sensor Enclosed Type 140Vp-P For Closed Obstacle Detection

MSW-P1040H08TR

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Description

Mini Long Range Distance Sensor Enclosed Type 140Vp-P For Closed Obstacle Detection

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Quick details:

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1. Dimension: 10mm(D)*8.0mm(H)

2. Center?frequency?:40.0±1.0KHz
3. Using Method: act both as?transmitter or receiver.
4. Construction:Enclosed type

5. Echo Sensitvity: ≥100mV

6. Decay Time: ≤2.0ms

7. Directivity?Deg?:80°±15°??(-6dB)
8. Capacitance?:2000±20%pF?

9. Max.Input?Voltage:140Vp-p

10. Typical?Sensing?Range?:?0.3~3.0m?
11. Operating?Temperature?:-20℃?~+70℃
12. Storage?Temperature:-40℃?~+85℃

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Drawing(mm)

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# Features

1) Water proof?and?dual?use

2)?Compact?and?light?weight.

3)?High?sensitivity?and?sound?pressure

4)?Less?power?consumption

5)?High?reliability

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Packaging



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The main function of the ultrasonic sensor are transmitting and receiving. Ultrasonic sensors provide easy method of distance measurement. defined as electronic devices that emit an acoustic wave beyond the upper range of human hearing called the audible range, between 20 hertz and 20 kilohertz ?and determine the distance between the sensor and an object based on the time it takes to send the signal and receive the echo. generic distance measurement, and commercial fish finders, among other applications.

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How does it work?

The Ultrasonic Sensor sends out a high-frequency sound pulse and then times how long it takes for the echo of the sound to reflect back. The sensor has 2 openings on its front. One opening transmits ultrasonic waves, (like a tiny speaker), the other receives them, (like a tiny microphone).

The speed of sound is approximately 341 meters (1100 feet) per second in air. The ultrasonic sensor uses this information along with the time difference between sending and receiving the sound pulse to determine the distance to an object. It uses the following mathematical equation:
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How to calculate the time?

Time = the time between when an ultrasonic wave is transmitted and when it is received.You divide this number by 2 because the sound wave has to travel to the object and back.

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